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fixed bug in avoid_readback disk cache algorithm

This commit is contained in:
Arvid Norberg 2011-03-26 19:06:58 +00:00
parent 3d826ae32f
commit 41bc60c36a
1 changed files with 25 additions and 5 deletions
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30
src/disk_io_thread.cpp
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@ -422,12 +422,23 @@ namespace libtorrent
{
TORRENT_ASSERT(i->storage);
flush_range(const_cast<cached_piece_entry&>(*i), 0, INT_MAX, l);
TORRENT_ASSERT(i->num_blocks == 0);
// we want to keep the piece in here to have an accurate
// number for next_block_to_hash, if we're in avoid_readback mode
if (m_settings.disk_cache_algorithm != session_settings::avoid_readback)
widx.erase(i++);
else
++i;
bool erase = m_settings.disk_cache_algorithm != session_settings::avoid_readback;
if (!erase)
{
// however, if we've already hashed the whole piece, in-order
// there's no need to keep it around
int piece_size = i->storage->info()->piece_size(i->piece);
int blocks_in_piece = (piece_size + m_block_size - 1) / m_block_size;
erase = i->next_block_to_hash == blocks_in_piece;
}
if (erase) widx.erase(i++);
else ++i;
}
if (m_settings.explicit_read_cache) return;
@ -633,6 +644,9 @@ namespace libtorrent
if (options & dont_flush_write_blocks) return ret;
// if we don't have any blocks in the cache, no need to go look for any
if (m_cache_stats.cache_size == 0) return ret;
if (m_settings.disk_cache_algorithm == session_settings::lru)
{
cache_lru_index_t& idx = m_pieces.get<1>();
@ -673,6 +687,8 @@ namespace libtorrent
while (end < blocks_in_piece && i->blocks[end].buf) ++end;
tmp = flush_range(p, start, end, l);
p.num_contiguous_blocks = contiguous_blocks(p);
if (i->num_blocks == 0 && i->next_block_to_hash == blocks_in_piece)
idx.erase(i);
blocks -= tmp;
ret += tmp;
if (blocks <= 0) break;
@ -683,8 +699,12 @@ namespace libtorrent
while (blocks > 0)
{
cache_lru_index_t::iterator i = std::max_element(idx.begin(), idx.end(), &cmp_contiguous);
if (i == idx.end()) return ret;
if (i == idx.end() || i->num_blocks == 0) return ret;
tmp = flush_contiguous_blocks(const_cast<cached_piece_entry&>(*i), l);
// at this point, we will for sure need a read-back for
// this piece anyway. We might as well save some time looping
// over the disk cache by deleting the entry
if (i->num_blocks == 0) idx.erase(i);
blocks -= tmp;
ret += tmp;
}