Obtain password length from utils script

This commit is contained in:
Bob Mottram 2016-07-03 17:25:14 +01:00
parent cc26414f23
commit 88d2df7ba6
1 changed files with 2 additions and 2 deletions

View File

@ -45,10 +45,10 @@ FREEDOMBONE_WEBSITE="http://freedombone.uk.to"
# Minimum number of characters in a password
MINIMUM_PASSWORD_LENGTH=10
if [ -f /usr/local/bin/${PROJECT_NAME} ]; then
MINIMUM_PASSWORD_LENGTH=$(cat /usr/local/bin/${PROJECT_NAME} | grep 'MINIMUM_PASSWORD_LENGTH=' | head -n 1 | awk -F '=' '{print $2}')
MINIMUM_PASSWORD_LENGTH=$(cat /usr/local/bin/${PROJECT_NAME}-utils-passwords | grep 'MINIMUM_PASSWORD_LENGTH=' | head -n 1 | awk -F '=' '{print $2}')
else
if [ -f /usr/bin/${PROJECT_NAME} ]; then
MINIMUM_PASSWORD_LENGTH=$(cat /usr/bin/${PROJECT_NAME} | grep 'MINIMUM_PASSWORD_LENGTH=' | head -n 1 | awk -F '=' '{print $2}')
MINIMUM_PASSWORD_LENGTH=$(cat /usr/bin/${PROJECT_NAME}-utils-passwords | grep 'MINIMUM_PASSWORD_LENGTH=' | head -n 1 | awk -F '=' '{print $2}')
fi
fi