msvcrt: Fix [str|wcs]tod result being compared against FLT_MAX.
Also a more straightforward way of fixing the tests on i386 Linux. Wine-Bug: https://bugs.winehq.org/show_bug.cgi?id=48324 Signed-off-by: Erich E. Hoover <erich.e.hoover@gmail.com> Signed-off-by: Alexandre Julliard <julliard@winehq.org>
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@ -49,6 +49,8 @@
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#define MSVCRT_I64_MIN (-MSVCRT_I64_MAX-1)
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#define MSVCRT_UI64_MAX (((unsigned __int64)0xffffffff << 32) | 0xffffffff)
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#define MSVCRT_MB_LEN_MAX 5
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#define MSVCRT_FLT_MAX_10_EXP 38
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#define MSVCRT_FLT_MIN_10_EXP (-37)
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#define MSVCRT_DBL_MAX_10_EXP 308
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#define MSVCRT_DBL_MIN_10_EXP (-307)
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#ifdef _WIN64
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@ -571,10 +571,10 @@ static double MSVCRT_mul_pow10(double x, int exp)
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static double strtod_helper(const char *str, char **end, MSVCRT__locale_t locale, int *err)
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{
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BOOL found_digit = FALSE, overflow, underflow;
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int exp1=0, exp2=0, exp3=0, sign=1;
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MSVCRT_pthreadlocinfo locinfo;
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unsigned __int64 d=0, hlp;
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BOOL found_digit = FALSE;
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unsigned fpcontrol;
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const char *p;
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double ret;
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@ -694,18 +694,12 @@ static double strtod_helper(const char *str, char **end, MSVCRT__locale_t locale
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|MSVCRT__EM_OVERFLOW|MSVCRT__EM_UNDERFLOW|MSVCRT__EM_INEXACT|MSVCRT__PC_64,
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MSVCRT__MCW_EM | MSVCRT__MCW_PC );
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/* if we have a simple case then just calculate the result directly */
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overflow = (exp3-exp1 > MSVCRT_DBL_MAX_10_EXP);
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underflow = (exp3-exp1 < MSVCRT_DBL_MIN_10_EXP);
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if(!overflow && !underflow) {
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exp1 += exp3;
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exp3 = 0;
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}
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/* take the number without exponent and convert it into a double */
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ret = MSVCRT_mul_pow10(d, exp1);
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/* shift the number to the representation where the first non-zero digit is in the ones place */
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if(overflow || underflow)
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exp2 = (ret != 0.0 ? (int)log10(ret) : 0);
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exp2 = (ret != 0.0 ? (int)round(log10(ret)) : 0);
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if (exp3-exp2 >= MSVCRT_FLT_MIN_10_EXP && exp3-exp2 <= MSVCRT_FLT_MAX_10_EXP)
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exp2 = 0; /* only bother to take this extra step with very small or very large numbers */
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/* incorporate an additional shift to deal with floating point denormal values (if necessary) */
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if(exp3-exp2 < MSVCRT_DBL_MIN_10_EXP)
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exp2 += exp3-exp2-MSVCRT_DBL_MIN_10_EXP;
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@ -1999,8 +1999,11 @@ static void test__strtod(void)
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strtod("-1d309", NULL);
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ok(errno == ERANGE, "errno = %x\n", errno);
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d = strtod("3.4028234663852887e38", NULL);
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ok(d <= FLT_MAX, "d = %e\n", d);
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d = strtod("1.7976931348623158e+308", NULL);
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ok(almost_equal(d, DBL_MAX), "d = %lf (%lf)\n", d, DBL_MAX);
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ok(d == DBL_MAX, "d = %le\n", d);
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}
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static void test_mbstowcs(void)
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@ -398,10 +398,10 @@ static double MSVCRT_mul_pow10(double x, int exp)
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double CDECL MSVCRT__wcstod_l(const MSVCRT_wchar_t* str, MSVCRT_wchar_t** end,
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MSVCRT__locale_t locale)
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{
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BOOL found_digit = FALSE, overflow, underflow;
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int exp1=0, exp2=0, exp3=0, sign=1;
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MSVCRT_pthreadlocinfo locinfo;
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unsigned __int64 d=0, hlp;
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BOOL found_digit = FALSE;
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unsigned fpcontrol;
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const MSVCRT_wchar_t *p;
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double ret;
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@ -490,18 +490,12 @@ double CDECL MSVCRT__wcstod_l(const MSVCRT_wchar_t* str, MSVCRT_wchar_t** end,
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|MSVCRT__EM_OVERFLOW|MSVCRT__EM_UNDERFLOW|MSVCRT__EM_INEXACT|MSVCRT__PC_64,
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MSVCRT__MCW_EM | MSVCRT__MCW_PC );
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/* if we have a simple case then just calculate the result directly */
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overflow = (exp3-exp1 > MSVCRT_DBL_MAX_10_EXP);
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underflow = (exp3-exp1 < MSVCRT_DBL_MIN_10_EXP);
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if(!overflow && !underflow) {
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exp1 += exp3;
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exp3 = 0;
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}
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/* take the number without exponent and convert it into a double */
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ret = MSVCRT_mul_pow10(d, exp1);
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/* shift the number to the representation where the first non-zero digit is in the ones place */
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if(overflow || underflow)
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exp2 = (ret != 0.0 ? (int)log10(ret) : 0);
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exp2 = (ret != 0.0 ? (int)round(log10(ret)) : 0);
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if (exp3-exp2 >= MSVCRT_FLT_MIN_10_EXP && exp3-exp2 <= MSVCRT_FLT_MAX_10_EXP)
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exp2 = 0; /* only bother to take this extra step with very small or very large numbers */
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/* incorporate an additional shift to deal with floating point denormal values (if necessary) */
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if(exp3-exp2 < MSVCRT_DBL_MIN_10_EXP)
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exp2 += exp3-exp2-MSVCRT_DBL_MIN_10_EXP;
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